How can the electric potential in the exact center of two equal but opposite charges be
zero, but the electric field be non zero?
Asked by:
Joe
Answer
It can be; and more often than not the electric field will be nonzero where the electric potential is zero.
Let us first state what these quantities, i.e. electric potential and electric field,
mean.
The electric potential is a scalar quantity which quantifies the amount of electrical
potential energy a unit test charge would have if it were placed at a specific point in
space. ('Test charge' means that the charge is brought to that location without disturbing
the other charges.)
In contrast, the electric field is a vector quantity (meaning it has both a magnitude and
a direction). It quantifies the force a unit test charge would experience if it were
placed at a specific point in space.
These two quantities are related very closely,
since force is the negative of the derivative of the potential energy, the electric field
is the negative gradient (gradient, simply put, is a fancy name for derivative in three
dimensions) of the electric potential.
In other words, the electric field is a measure of how quickly the electric potential
changes, and it points in the direction of maximum negative change of the electric
potential. Thus, the value of the electric potential at that point is not directly related
to the electric potential at that point. What matters is how fast the electric potential
_changes_ around the point in question.
In the example given in the question, the potential is zero in the mid-point, but it
changes quite rapidly when one moves towards one charge or the other. So, although the
electric potential is zero, the field is nonzero.
Let me try to explain by analogy. The case of a car on a road is analogous to this. The
elevation of the car from sea level determines is analogous to the electric potential (it
is the gravitational potential), and the force on the car is analogous to the electric
field. Now, the force on the car is determined by the slope of the road (derivative,
gradient) and not by the elevation of the road from sea level. In other words, if your car
was on a road which is sloping down, it _would_ experience a downhill force even if at
that moment it happened to be at exactly sea level (i.e. the potential was zero). In fact,
the force depends only on the slope, and it would be unaltered if the same road was
carried to a different elevation. (Well, almost, since gravity does change with altitude,
but I hope you get the point.)
There is another point... The 'zero point' of any potential is arbitrary. (At least I do
not know of any counterexample.) Using a certain reference may be _convenient_, (such as
no charges around = zero potential or sea level = zero potential) but any other choice
works just as well. It may make the math more complicated, but it will produce the same
physical results. This is because only _changes_ in potential have any physical
significance.
Answered by:
Yasar Safkan, Ph.D., Software Engineer, Noktalar A.S., Istanbul, Turkey
'For the sake of persons of ... different types, scientific truth should be presented in different forms, and should be regarded as equally scientific, whether it appears in the robust form and the vivid coloring of a physical illustration, or in the tenuity and paleness of a symbolic expression.'